Calculate the quantity of heat, in kilojoules, (a) required to raise the temperature of 9.25 L of water from 22.0 to 29.4 °C; (b) associated with a 33.5 °C decrease in temperature in a 5.85 kg aluminum bar (specific heat of aluminium = 0.903 J g-1 °C-1)
SOLUTION
(a)
V
water = 9.25 L
= 9.25 L x (1000 cm3 L-1)
= 9250 cm3
ρ
water = 1 g cm-3
m
water = V . ρ
= 9250 cm3 x 1 g cm-3
= 9250 g
Cp
water = 4.18 J g-1
°C-1
dT = 29.4
°C – 22.0 °C
= 7.4 °C
Q = m Cp dT
= 9250 g x 4.18 J g-1 °C-1 x 7.4 °C
= 286.121 KJ
(b)
m aluminium = 5.85 kg
= 5850 g
Cp aluminium = 0.903 J g-1 °C-1
Q = 5850 g x 0.903 J g-1 °C-1 x (-33.5 °C)
= -176965.425 J
= -176.965425 KJ
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