Home » » Solution Manual - General Chemistry 10th edition - Chapter 7 - Exercises - Heat Capacity (Specific Heat) - Number 1 page 283

Solution Manual - General Chemistry 10th edition - Chapter 7 - Exercises - Heat Capacity (Specific Heat) - Number 1 page 283

QUESTION

Calculate the quantity of heat, in kilojoules, (a) required to raise the temperature of 9.25 L of water from 22.0 to 29.4 °C; (b) associated with a 33.5 °C decrease in temperature in a 5.85 kg aluminum bar (specific heat of aluminium = 0.903 J g-1 °C-1)




SOLUTION

(a)

V water         =   9.25 L
                   =   9.25 L x (1000 cm3 L-1)
                   =   9250 cm3

ρ water          =   1 g cm-3

m water         =   V . ρ
                   =   9250 cm3 x 1 g cm-3
                   =   9250 g

Cp water       =   4.18 J g-1 °C-1

dT              =   29.4 °C – 22.0 °C
                   =   7.4 °C

Q                =   m Cp dT
                   =   9250 g     x     4.18 J g-1 °C-1     x     7.4 °C
                   =   286.121 KJ



(b)
aluminium   =   5.85 kg
                      =   5850 g

Cp aluminium  =   0.903 J g-1 °C-1

Q                   =   5850 g     x     0.903 J g-1 °C-1     x     (-33.5 °C)
                      =   -176965.425 J
                      =   -176.965425 KJ

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